Answer: The osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.
Explanation:
Given: Mass = 5.0 g
Volume = 1 L
Molar mass of sucrose = 342.3 g/mol
Moles are the mass of a substance divided by its molar mass. So, moles of sucrose are calculated as follows.
Hence, concentration of sucrose is calculated as follows.
Formula used to calculate osmotic pressure is as follows.
where,
= osmotic pressure
C = concentration
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Thus, we can conclude that the osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.
Answer:
79.904 g/mol
Explanation:
The molar mass of bromine is 79.904 g/mol.
Answer:
The solution to the question is as follows
(a) The rate of ammonia formation = 0.061 M/s
(b) the rate of N₂ consumption = 0.0303 M/s
Explanation:
(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃
N₂(g) + 3H₂(g) → 2NH₃(g)
The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have
3 moles of H₂ reacts to form 2 moles of NH₃, therefore
0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃
Hence the rate of ammonia formation is 0.061 M/s
(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence
0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂
Therefore the rate of consumption of N₂ = 0.0303 M/s
this is so ez,
ok so here what u'll do after u balance the equation:
1. convert grams of oxygen to moles of oxygen.
2. convert moles of oxygen to moles of water
3. convert moles of water to grams of water.
4. bOOm... that's your answer
as follows:
2H2O(l)===>2H2(g)+O2(g)
1. 151200(g)/16(g/mol)=9540 moles of O2
2. 9450 moles of O2 × 2 moles of H2O =18900 moles of H2O
3. 18900 moles of H2O × 10g/mol = 189000g of H2O is required.
