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Wewaii [24]
2 years ago
15

What pressure is requred to contain 0.023 moles of nitrogen gas in a 4.2 L container at a

Chemistry
1 answer:
zubka84 [21]2 years ago
5 0

Answer:

0.13 atm

Explanation:

Using the Ideal Gas Law; PV=nRT, we can rearrange to solve for pressure.

P=nRT/V

P is pressure, n is number of moles (0.023), R is a constant (0.08206 L*atm/mol*K), T is temperature in Kelvin (293.15K) and V is volume, 4.2 L.

So, plugging in;

P=(0.023mol)(0.08206L*atm/mol*K)(293.15K)/(4.2 L)

P=0.1317 atm

P=0.13 atm; multiply by 760 to get to Torr or mmHg.

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What is the mass of the block of iron illustrated below?
Mandarinka [93]
VOLUME= 5cm*10cm*2cm =100cm^3
but density of iron=7.874g/cm^3
mass=7.874g*100 =787.4g
mass of that block = 787.4g
7 0
3 years ago
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Classify the following reaction *
hichkok12 [17]

Answer:

double replacement

Explanation:

The reaction equation is given as:

       Pb(NO₃)₂  +  2KI   →   PbI₂ +   KNO₃

This reaction is a double displacement reaction.

In this form of reaction, there is an actual exchange of partners to form new compounds.

      AB + CD →  AD + CD

One of the following condition serves as driving force for the reaction:

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5 0
3 years ago
Cuantos gramos de hidróxido de calcio se necesitan para preparar 875ml de solución al 2M​
PtichkaEL [24]

Answer:

129,66 g

Explanation:

Desde,

Número de moles = concentración * volumen

concentración = 2 M

volumen = 875 ml

Número de lunares = 2 * 875/1000

Número de lunares = 1,75 moles

Número de moles = masa / masa molar

masa molar de hidróxido de calcio = 74.093 g / mol

1,75 moles = masa / 74,093 g / mol

masa = 1,75 moles * 74,093 g / mol

masa = 129,66 g

7 0
3 years ago
Structure of 2,6-diiodo-4-methyl-5-propylheptane​
ira [324]

Explanation:

2,6-Dibromo-4-isopropylphenol

2432-16-8

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4-isopropyl-2,6-dibromophenol

5 0
3 years ago
a piece of newly synthesized material of mass 25.0 g at 80.0C is placed in a calorimeter containing 100.0 g of water at 20.0C. I
serg [7]

Answer:

The correct answer is 1.194 J/g.ºC

Explanation:

The heat released by the material is absorbed by the water. We put a minus sign (-) for a released heat and a plus sign (+) for an absorbed heat.

We know the mass of the material (mass mat= 25.0 g) and the mass of water (mass H20= 100.0 g) and the specific heat capacity of water is known (Shw=4.18 J/g.ºC), so we can equal the heat released by the material and the heat absorbed by water y calculate the specific heat capacity of the material (Shm) as follows:

heat released by material = heat absorbed by water

-(mass material x Shm x ΔT)= mass water x Shw x ΔT

-(25.0 g x Shm x (24ºC - 80ºC)= 100.0 g x 4.18 J/g.ºC  x (24ºC-20ºC)

25.0 g x Shm x (56ºC) =  100.0 g x 4.18 J/g.ºC x 4ºC

⇒Shm= (100.0 g x 4.18 J/g.ºC x 4ºC)/(25.0 g x 56ºC)

 Shm= 1.194 J/g.ºC

5 0
3 years ago
Read 2 more answers
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