In terms of workplace we need our safety measures to have a safe and to ensure the awareness of health and safety of every personnel, waste disposal and the security. Speaking of security every laboratories have their own security, well organized and the most important to store information safely and the other data. The information can be stored in LIMS (laboratory information management system) by registration all the samples. You can any kind of device to upload the information.
Heat
gained in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. From
this, we can calculate things. We do as follows:
<span>Heat gained =
Heat lost</span>
mC(T2-T1) = - mC(T2-T1)
C(liquid water) = 4.18 J/gC
C(ice) = 2.11 J/gC
</span><span>(354 mL)(1.0 g/mL)(4.18 J/gC)(26 C - 6 C) = m(2.11 J/gC)(6 - 0C) </span><span>
m = 2337.63 g of ice
</span>
I believe that it is petroleum ether.
Answer:
The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :
<u>Difference</u> <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>
Explanation:
<u>Part I :</u>
n = 4.9983
n = 4.99 moles
(Note : You can also take n = 5 mole )
Molar mass of gold = 196.96 g/mole
This means, 1 mole of gold(Au) contain = 196.96 grams
So, 4.99 moles of gold contain = 
g
4.99 moles of gold contain = 984.8 g
Mass of 
atoms of gold = 984.5 g
<u>Part II :</u>
Density of Gold = 
Volume of the cuboid = 
Volume of the gold bar =
Volume of the gold bar = 51
Using formula,
Mass = 985.32 g
So, A gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>
<u>Difference</u> <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>
M1V1 = M2V2
M1 = 3.000 M
V1 = 0.8000 L
M2 = ?
V2 = 2.00 L
M2 = M1V1/V2 = (3.000 M)(0.8000 L)/(2.00 L) = 1.20 M
