All categories

3 years ago

PLEASE HELP ME WITH THIS!!!

Mathematics

1 answer:

kramer3 years ago

7 0

I want to say the answer is 9

You might be interested in

HELP ASAPP 30 points!!!!!<br> Which number is rational?

Anna35 [415]

Answer:

Step-by-step explanation:

because its a whole number as in the square root is 4

6 0

2 years ago

The Question

77julia77 [94]

Answer:

Step-by-step explanation:

Divide 12 by .40 (the percentage) to figure out what the full number would be.

5 0

3 years ago

What is the slope of the line that passes through the points (6, 2) and (4, 10)?

drek231 [11]

Answer:

-4

Step-by-step explanation:

Slope = y2 - y1/x2 - x1

Given

x1 = 6

y1 = 2

x2 = 4

y2 = 10

Therefore

Slope = 10 - 2/4 - 6

= 8/-2

= -4

5 0

3 years ago

Read 2 more answers

Which of the following identifies when food is most susceptible to bacteria and microorganism growth?

snow_lady [41]

The correct answer is summer because of heat

4 0

3 years ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago