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stira [4]
3 years ago
9

What is the following product? 3^sqr4 * sqr3​

Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

9sqrt3

Step-by-step explanation:

This is an order of operations question.

First, simply the exponent, which gives you 3^2*sqrt3

Next, 3^2=9, giving the final answer of 9sqrt3.

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Write the equation or inequality : in order to take honors level math , Lisa must have an average of 85 on her math tests. Her s
Minchanka [31]

Answer:

Lisa must score 89 in fourth test.

4 0
3 years ago
45x squared OVER x minus 9
poizon [28]
<u>45x²</u> · <u>x² - 5x - 36</u> = <u>45x²(x² - 5x - 36)</u> = <u>45x⁴ - 225x³ - 1620x²</u> =   
x - 9    x³ + 12x²       (x - 9)(x³ + 12x²)          x⁴ + 3x³ - 108x²
45 with a remainder of  -360x³ + 3240x²
4 0
3 years ago
What is the surface area of a square pyramid that has an 8 cm base length and triangular faces that are 14 cm tall? square centi
tatiyna
It's around 296.96 cm^2



good luck
7 0
3 years ago
Read 2 more answers
6÷2(1+2)= _____ whats the answer to this
GalinKa [24]

Answer:

9

Step-by-step explanation:

You do parenthesis first so 1+2=3

Then you do division 6 divided by 2=3

Then you will multiply 3 by 3 so 9

This is known as pemdas

P=parenthesis

E=exponents

MD=multiplication and division you do it left to right so if division is in front of multiplication then you do division

As=Addition and subtraction is also left to right

8 0
2 years ago
Read 2 more answers
0/1
pychu [463]

Answer:

68.8 sq. inches.

Step-by-step explanation:

The triangular surfaces have sides 2 in by 3 in by 4 in.

So, half perimeter, s = \frac{2 + 3 + 4}{2} = 4.5

So, the area of the triangular face is \sqrt{s(s - 4)(s - 2)(s - 3)} = \sqrt{4.5 \times 0.5 \times 2.5 \times 1.5} = 2.9 sq. inches.

Now, the total surface area of the right triangular prism will be (2.9 × 2) + 7(2 + 3 + 4) = 68.8 sq. inches. (Answer)

4 0
2 years ago
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