Answer:
(c) 118/V100 11.8
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
In this problem, we have that:
So
So the correct answer is:
(c) 118/V100 11.8
Answer: f) None of the above
= ( 5.283, 5.917)
Therefore at 90% confidence interval (a,b) = ( 5.283, 5.917)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 5.6ft
Standard deviation r = 1.0ft
Number of samples n = 27
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
5.6+/-1.645(1.0/√27)
5.6+/-1.645(0.192)
5.6+/-0.317 ft
= ( 5.283, 5.917)
Therefore at 90% confidence interval (a,b) = ( 5.283, 5.917)
Answer: 0 slope, horizontal line.
Step-by-step explanation:
when using y2-y1/x2-x1, you would get 8-(-3)/5-5. This simplifies to 11/0, which means that the line would have 0 slope. A line with 0 slope is a horizontal line.
Answer:
RQ = 10
Step-by-step explanation:
When two triangles are similar, the ratio of their corresponding sides are equal;
Thus, we have it that;
QP/RQ = BC/AB
12/RQ = 36/30
RQ = 12 * 30/36 = 10
Step-by-step explanation:
1 - ((9*t) - (9*-2) = ( 4*t) - (4*-15)
1 - 9t + 18 = 4t + 60
- 9t - 4t = 60 - 1 - 18
-13t = 40
t = 40/-13
