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3 years ago

6

Beginning with the quadratic equation y=ax to the power of 2 + bx+c , Fred calculated -b/2a and then plugged that number in for

X to get a Y. What is one reason he might have done this?

1 answer:

postnew [5]3 years ago

6 0

To find the vertex of the parabola.

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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-7, -5), B(-

sergey [27]

The length of side CD is equal to 11 units.

Given coordinates of rectangle are A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5)

We are require to find the length of side CD.

Rectangle is a two dimensional figure whose two opposite sides are equal to each other. Distance between two coordinates is the equal to length of a side.

We know that the distance means how far two points are located.

Coordinates of A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5).

Distance= $\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$ where ( $x_{1} ,y_{2} )(x_{2} ,y_{2} )$ are the coordinates of two ends of a line.

CD= $\sqrt{(-5-6)^{2} +(-4+4)^{2} }$

= $\sqrt{11^{2}+0^{2} }$

= $\sqrt{121}$

=11 units.

Hence the length of side CD is 11 units.

Learn more about distance at brainly.com/question/17273444

#SPJ4

Question is wrong as it should be :

Coordinates of rectangle A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5) and find the length of CD.

8 0

2 years ago

Please answer the following

nikitadnepr [17]

The first part of the answer is 20x+9
Second part is 4a-6b

3 0

3 years ago

Ayuda necesito en el ultimo punto

Sonbull [250]

Answer:

Please refrain from using Spanish in a English brainliest site.

Step-by-step explanation:

8 0

3 years ago

Please narrate every step you make and make a 2 column proof!<br><br>thank you!!

quester [9]

Hang on ,it is already proven through given .

So The proof is of one line only

ray FEH bisects <DFG (Given)

Hence proved .

4 0

2 years ago

Read 2 more answers

Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t

MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6. $\overline 6$

Given that 6. $\overline 6$ > 0, we have;

At the maximum volume, the width of the block, w = 6. $\overline 6$ cm ≈ 6.7 cm

The maximum volume, $V_{max}$ , is therefore given when w = 6. $\overline 6$ cm = 20/3 cm as follows;

V = 10·w² - w³

$V_{max}$ = 10·(20/3)² - (20/3)³ = 4000/27 = 148. $\overline {148}$

The maximum volume, $V_{max}$ = 148. $\overline {148}$ cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0

3 years ago