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3 years ago

The Mason family's bill for dinner is $55.73. How much should they tip their server? (Assuming they tip the normal 15%)

Mathematics

1 answer:

Lisa [10]3 years ago

5 0

Answer:$8.36

Step-by-step explanation:

Change % to decimal and multiply

15% =.15

55.73 x .15 = 8.3595

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Number 4 pleeeaaassseee

dmitriy555 [2]

This is simple, cycle through the answers until you get 30 inches squared. The answer is height equals 5. 2x3x5=30

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3 years ago

Which of the following completes the rule for this translation, (x, y) → (x + 4, ___)?

morpeh [17]

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2 years ago

What is the length of the conjugate axis? <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac

LuckyWell [14K]

Answer:

the length of the conjugate axis is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

$\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1$

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

$\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1$

Then

$b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16$

Finally the length of the conjugate axis is 16

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \

SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

Given:

A1 = 2 units

d1= 5 cm

A2 = 8 units

To find:

Distance of separation when the force of attraction is 8 units d2 = ?

Solution:

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

Answer: the distance between the two objects is 2.5 cm, if the attraction between them is 8 units.

Learn more about universal law of gravitation here brainly.com/question/27244479

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2 years ago

Write down the letter of the shape that is congruent to the shaded shaPe

guapka [62]

Answer:

E looks like it is most congruent

Step-by-step explanation:

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2 years ago