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Mashcka [7]
3 years ago
14

Daca AB = 18cm DB = 12cm DE = 4cm si AE = 9cm, clalculati AD, BC, AC si EC?

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
I got 43 as my answer hope this helps
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What is 36j + j<br><br> please help and explain if you can!!! :)
Norma-Jean [14]
36j + j = 37j

Explanation.
You could translate this sum into a normal sebtence: I have 36 apples and add 1 apple more.

The sum will then be 36 apples + apple = 37 apples.
Replacing the word (in this explanation 'apple') by a letter learns us 36a + a = 37a

Hence 36j + j = 37j
8 0
3 years ago
Change 0.275 to a fraction
goldenfox [79]
<span>Well, the number is decimal form, is in the thousandths place, so the denominator, would be 1000's: 
<em><u>0.275 = 275⁄1000</u></em></span><em><u> </u></em>
<span>Then, you have to Simplify 275⁄1000 In which, you would get: <em><u> 11⁄40</u></em></span><span><em><u> </u></em></span>
8 0
3 years ago
Read 2 more answers
PLEASE HELP! Economics
pashok25 [27]

Answer: b

Step-by-step explanation:

if u stop imports  then u have money

4 0
2 years ago
Read 2 more answers
Can anyone help with this?
Karo-lina-s [1.5K]
The answer is B. If you take the even root of a positive number, you'll get two solutions, a positive and a negative
4 0
3 years ago
I need some help please!
adell [148]

Answer:

8 seconds

Step-by-step explanation:

lets first start by plugging in 1024 into initial height

h(t) = -16t^2 + 1024

I would find a Greatest Common Factor (GCF) first

-16(t^2 - 64)     If this is new just think that if you multiply -16 by t squared and -64 you will come back to the original equation

But now we notice that T squared -64 can be factored with the difference of perfect squared method

so we will get -16(t-8)(t+8)

So to get the answers we will set everything equal to 0

-16t =0

t =0 this is the time that the penny was thrown

t-8 = 0

t = 8 the is the time the penny hit the ground

t+8 =0

t= -8 This is an extraneous solution or a solution that doesn't make sense so we just disregard the solution.

3 0
3 years ago
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