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3 years ago

Please help thanks!!!

Mathematics

2 answers:

Julli [10]3 years ago

5 0

The first one is the answer

VladimirAG [237]3 years ago

4 0

Answer:

2x+8

Step-by-step explanation:

So when they say a number, they mean a unknown value.

We can use a variable as this unknown value. In this situration we can call it x.

This phase says "twice a number" or "twice x". This can be though of as 2x.

next it says this number is increased by 8. When they say increased they meanm added to.

So 8 is added to 2x. Or 2x + 8

So its the second answer, 2x+8.

Hope this helps!

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2 years ago

7.) x-3>4 please help

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6 0

3 years ago

Read 2 more answers

What is 22 percent of 50

Lady_Fox [76]

Translate
'what' means unknown or find this or ?
'is' means = or equals
22%
'of' means multiply
50

percent means parts out of 100
x%=x/100 so 22%=22/100

so

what is 22% of 50 means
?=22/100 times 50
?=1100/100
?=11
answer is 11

the hack, is to recognize that 50 is 1/2 of 100, so 22% of 1/2 of 100 is 22/2=11

answe ris 11

5 0

3 years ago

Read 2 more answers

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago