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Serhud [2]
3 years ago
11

Evaluate the polynomial when x=4 y=-4 x^2-3y^2+2xy

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0
x^2-3y^2+2xy\\\\for\ x=4\ and\ y=-4\\\\substitute\ the\ values\ of\ x\ and\ y:\\\\4^2-3\cdot(-4)^2+2\cdot4\cdot(-4)=16-3\cdpt16-32=16-48-32=-64
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All you have to do is add \frac{1}{4} 15 times to get that number.

\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} = 3.75

You can also do 15 times \frac{1}{4}, which will result in the same thing.

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