Evaluate the polynomial when x=4 y=-4 x^2-3y^2+2xy

1 answer:

4 0

$x^2-3y^2+2xy\\\\for\ x=4\ and\ y=-4\\\\substitute\ the\ values\ of\ x\ and\ y:\\\\4^2-3\cdot(-4)^2+2\cdot4\cdot(-4)=16-3\cdpt16-32=16-48-32=-64$

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Harman [31]

The answer would be x equals 4

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3 years ago

Alborosie

I can’t see the image maybe if you redo it

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3 years ago

GREYUIT [131]

Can you add the picture ?? If you don’t mind?? It helps me Answer better

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1 year ago

scoundrel [369]

Answer:

5/6

Step-by-step explanation:

1/3 = 2/6

1/2 = 3/6

2/6+3/6= 5/6

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2 years ago

Ivan

$0.3 * 0.6$

$6*3 = 18$

$0.18$

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2 years ago