We should first find the gas mileage
that will be 535/21 equals to 25.5
The car's gas mileage is 25.5
To find how much the car can drive on 51 gallons of gas
25.5×51
Equals to 1300.5
the car can drive 1300.5 miles on 51 gallons of gas
A. (f + g)(x) = f(x) + g(x) = 4x - 5 + 3x + 9 = 7x + 4
B. f.g (x) = f(x) * g(x) = (4x - 5)*(3x + 9) = 12x^2 + 36x - 15x - 45
= 12x^2 + 21x - 45
C Replace the x in f(x) by g(x):-
= 4(3x + 9) - 5
= 12x + 36 - 5
= 12x + 31
The answer is 357 hope it helped
4/6
= (4/2) / (6/2)
= 2/3
6/12
= (6/6) / (12/6)
= 1/2
Because 2/3 ≠ 1/2, 4/6 and 6/12 are NOT equivalent.
Range: (-infinity, 4]
the ] signifies that the four is included in the range, rather than ) which means reaching but never approaching. this is why we use ( ) for - and + infinity, cause it can never be reached.
minimum: (-infinity, infinity)
keep it in same format as you have for the maximum
increasing
the interval -infinity
