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Vlad [161]
3 years ago
11

Clara Visits the aquarium while on vacation. The aquarium is 2 1/2 miles from her hotel. She walks 1/4 mile to the bus stop, tak

es the bus for 1 3/4 miles, and walks the rest of the way to the aquarium. How far did Clara walk after getting off the bus?
Mathematics
2 answers:
barxatty [35]3 years ago
4 0

Answer:

Distance she walked from bus stop to aquarium = 0.5 miles

Step-by-step explanation:

The aquarium is 2 1/2 miles from her hotel.

\texttt{Distance to aquarium = }2\frac{1}{2}=2.5miles

She walks 1/4 mile to the bus stop

\texttt{Distance she walked to bus stop = }\frac{1}{4}=0.25miles

She takes the bus for 1 3/4 miles

\texttt{Distance she traveled in bus = }1\frac{3}{4}=1.75miles

She walks from bus stop to aquarium

Distance she walked from bus stop to aquarium = 2.5 - 0.25 - 1.75 = 2.5 -2 = 0.5 miles

Distance she walked from bus stop to aquarium = 0.5 miles

anastassius [24]3 years ago
3 0
0.5 miles she had to walk
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"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that give
mestny [16]

Answer:

a. answer to a can be found in the attached file

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

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c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Step-by-step explanation:

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

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b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

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c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

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Download docx
7 0
4 years ago
Jasmine purchased 3 bags of hot cheetos and 2 packs of sour patch kids from the vending machine and spent 5.25. Michael also loa
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Answer:

cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

Step-by-step explanation:

Let the cost of a bag of hot cheetos be c

Let the cost of a pack of sour patch kids be k

Thus, for Jasmine, the equation will be;

3c + 2k = 5.25 - - - - (eq1)

For Michael, the equation will be;

7c + 3k = 9.75 - - - - - (eq2)

We will use method of elimination to solve this.

Multiply (eq 1) by 3 and (eq 2) by 2 to give;

9c + 6k = 15.75 - - (eq4)

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Subtract (eq4) from (eq 5) to get;

5c = 19.5 - 15.75

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Put 0.75 for c in (eq 4) to get;

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6k = 15.75 - 6.75

6k = 9

k = 9/6

k = 1.5

Thus; cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

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Since jason is currently at 54 feet above sea level and David is 11 feet below sea level the add 11 plus 54 which would give you 65 feet is there distance of elevations
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