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BARSIC [14]
4 years ago
8

What is the height after 2 seconds

%2B%2048" id="TexFormula1" title="h - - 16r {}^{2} + 32r + 48" alt="h - - 16r {}^{2} + 32r + 48" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Paladinen [302]4 years ago
6 0

Answer:

48

Step-by-step explanation:

It is given in the question that height of an object from his starting point as a function of time of travel in seconds of the object.

If height is given by h and time of travel is given by r seconds, then the height is given by

h = - 16r² + 32r + 48

Therefore, h after 2 seconds is - 16 (2)² + 32 (2) + 48 = 48.

Since height is positive so, we can conclude that after 2 secs the object will be 48 height above the initial position. (Answer)

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Explanation:

There are...

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We start with 6, and count down by 1 each time we fill up a slot. We stop once the third slot is filled or accounted for. The countdown is to ensure that we don't pick the same person twice. From here, multiply those values: 6*5*4 = 30*4 = 120

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As a slightly longer way to do the problem, you can use the nPr formula which is _nP_r = \frac{n!}{(n-r)!} where n = 6 and r = 3 in this case. The exclamation marks indicate factorial. If you go this route, you should find that one of the steps will involve 6*5*4.

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