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garik1379 [7]
2 years ago
11

A furniture store has a chair originally priced at $76 on sale for $58. What is the percent of decrease rounded to the nearest t

enth?
Mathematics
2 answers:
Ber [7]2 years ago
8 0

Answer:

23.7%

Step-by-step explanation:

If a  furniture store has a chair originally priced at $76 on sale for $58, the percent of decrease rounded to the nearest tenth is 23.7.

BabaBlast [244]2 years ago
7 0

Answer:

  23.7%

Step-by-step explanation:

The percentage change can be computed as ...

  ((new value)/(original value) -1) × 100%

  = (58/76 -1) × 100%

  ≈ (0.763 -1) × 100% = -23.7%

The decrease is 23.7%.

You might be interested in
Find the volume of this square based pyramid. 5 cm 5 cm 5 cm. Round to the nearest tenth.
vodka [1.7K]

Answer:

41.666 cm³ or 41.7 cm³  rounded to the nearest tenth.

Step-by-step explanation:

Volume of a square pyramid = base length² × height ÷ 3

25 × 5/3 = 41. 666

Have a great day:)

4 0
3 years ago
A farmer plants apple trees on a on a 235-acre farm. There are 47,000 apple trees evenly dispersed throughout the farm. How many
Musya8 [376]

Answer:

There are 200 trees per acre.

Step-by-step explanation:

47000 trees divided by 235 acres gets you 200 trees per acre.

When you go back and check your work, 200 trees per acre times 235 acres equals 47000 trees.

I hope this helps! :)

8 0
3 years ago
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
Help me pls i have been stuck on this for the past hour
Sedbober [7]

Answer:

-4, -6, -3, -5, -1. The inequality solved for n is n ≥ -6.

Step-by-step explanation:

Substitute all the values in the equation.

n/2 ≥ -3

-10/2 ≥ -3

-5 is not ≥ -3.

n/2 ≥ -3

-7/2 ≥ -3

-3.5 is not ≥ -3.

n/2 ≥ -3

-4/2 ≥ -3

-2 is ≥ -3.

n/2 ≥ -3

-9/2 ≥ -3

-4.5 is not ≥ -3.

n/2 ≥ -3

-6/2 ≥ -3

-3 is ≥ -3.

n/2 ≥ -3

-3/2 ≥ -3

-1.5 is ≥ -3.

n/2 ≥ -3

-8/2 ≥ -3

-4 is not ≥ -3.

n/2 ≥ -3

-5/2 ≥ -3

-2.5 is ≥ -3.

n/2 ≥ -3

-2/2 ≥ -3

-1 is ≥ -3.

To solve the inequality n/2 ≥ -3 for n, do these steps.

n/2 ≥ -3

Multiply by 2.

n ≥ -6.

3 0
3 years ago
What is the area of the figure
irinina [24]
It can’t be determined because there is too many numbers
3 0
3 years ago
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