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2 years ago

I don't understand this Geometry question. Can someone help, please?

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

3 0

The answer for the Geometry question is a=45s

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I'm stuck idkdmsjshhdhd

Klio2033 [76]

I hope this helps you

1)

a) 18/50

b) 6.1/3=2

c) 9/2.8/3=3.4=12

2)

1 1/2=1.2+1/2=3/2

3 3/4=3.4+3/4=15/4

if we can 12 muffins with 3/2 cups

how many muffins with 15/4

?.3/2=12.15/4

?=30 muffins

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3 years ago

The bar graph below shows the attendance at school dances. The ticket per price for each dance is $5 per student. Which two danc

topjm [15]

It's B because all the students that attended added together is 320 and 37.5 of 320 is 120

6 0

3 years ago

Use the Midpoint Rule with n = 5 to estimate the volume V obtained by rotating about the y-axis the region under the curve y = 1

velikii [3]

Using the shell method, the volume is given exactly by the definite integral,

$2\pi\displaystyle\int_0^1x(1+9x^3)\,\mathrm dx$

Splitting up the interval [0, 1] into 5 subintervals gives the partition,

[0, 1/5], [1/5, 2/5], [2/5, 3/5], [3/5, 4/5], [4/5, 5]

with left and right endpoints, respectively, for the $i$ -th subinterval

$\ell_i=\dfrac{i-1}5$

$r_i=\dfrac i5$

where $1\le i\le5$ . The midpoint of each subinterval is

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}{10}$

Then the Riemann sum approximating the integral above is

$2\pi\displaystyle\sum_{i=1}^5m_i(1+9{m_i}^3)\frac{1-0}5$

$\dfrac{2\pi}5\displaystyle\sum_{i=1}^5\left(\frac{2i-1}{10}+9\left(\frac{2i-1}{10}\right)^4\right)$

$\dfrac{2\pi}{5\cdot10^4}\displaystyle\sum_{i=1}^5\left(16i^4-32i^3+24i^2+1992i-999\right)=\frac{112,021\pi}{25,000}\approx\boxed{14.08}$

(compare to the actual value of the integral of about 14.45)

3 0

3 years ago

PLEASE HELP IT"S URGENT <br> Which figure has the greater Volume??

Aneli [31]

I cannot see the picture ?

6 0

3 years ago

The probability that a randomly selected point on the grid below is in the blue area is 9/16

DochEvi [55]

Answer:

The correct option is 1.

Step-by-step explanation:

it is given that the probability of a randomly selected point on the grid below is in the blue area is 9/16.

In the given grid we have only two colors that are blue and white.

Let A be the event of a randomly selected point on the given grid is in the blue area.

$P(A)=\frac{9}{16}$

If the randomly selected point on the given grid does not lie in the blue area, it means it lies on white area.

We will calculate P(A'), to find the probability that a randomly selected point is in the white on the grid.

We know that the sum of the probability is 1.

$P(A)+P(A')=1$

$P(A')=1-P(A)$

It is given that $P(A)=\frac{9}{16}$

$P(A')=1-\frac{9}{16}$

Therefore option 1 is correct.

8 0

2 years ago

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