A sample of size n taken from a population with mean = µ and standard deviation = σ has sample mean = µ and sample s.d. = σ/√n.
If the final exam scores are normally distributed, and X is a random variable for the mean of a sample, then
Pr[X < 70] = Pr[(X - 73) / (7.8/√24) < (70 - 73) / (7.8/√24)]
… ≈ Pr[Z < -1.8842]
… ≈ 0.0298
(where Z is normally distributed with µ = 0 and σ = 1).
Answer:
81 is the LCM of 81 and 3
Step-by-step explanation:
81 is the smallest (least) number that both (common) 81 and 3 "go into" (multiple)
81 goes into 81.
3 goes into 81.
81 is the smallest number that they both go into.
Answer:
21
Step-by-step explanation:
√1500 ≈ 38.7
round that up to 39 and square it:
39² = 1521
Answer:
The distance between them changing after 10 minutes will be 9.553 mph.
Step-by-step explanation:
The paths of two runners cross at a stop sign (O). One runner is heading south at a constant rate of 6.5 miles per hour towards A while the other runner is heading west at a constant rate of 7 miles per hour towards B.
So, after 10 minutes the first runner covers a distance of miles and the second runner covers a distance of miles.
Therefore, after 10 minutes their distance will be miles.
Now, the distance between them is given by
AB² = OA² + OB²
Now, differentiating this equation with respect to time t (in hours) we get
⇒
⇒
⇒ mph.
Therefore, the distance between them changing after 10 minutes will be 9.553 mph. (Answer)