Let H= No Hemophilia
h= Hemophilia
Now we will create the genotypes for the parents, it says that the mother is heterozygous which means she will carry the dominant and recessive allele, which would be Hh and it says the father is normal which would mean that he would be No Hemophilia dominant, so it would be HH
Cross the 2 created genotypes: Hh x HH
Now create your Punnett square using the 2 created genotypes above
H h
H HH Hh
H HH Hh
Looking at the Punnett square above, it appears that there’s a 2:2 ratio or a 50% chance of having Hemophilia and not having Hemophilia
So for a female child: 1/2 x 1/2= 1/4 of having a female with Hemophilia
The first one represents the female child having Hemophilia or not, that one can be obtained by simplifying the 2:2 ratio to a 1:1 ratio and the other one represents the chances of their child being a female. I assume that the steps above would be repeated again for the male child.
I hope that helps!
1a & b:Homozygous Recessive = ff - white flowers
Homozygous Dominant = FF - Purple flowers
Heterozygous = Ff - Purple flowers
2:The punnet square will look something like this
Tt Tttt tt
50% Heterozygous (with long thorns)
50% Homozygous Recessive (with short thorns)
Degrades the molecule
stabilizes the molecule
<span>increases the molecular concentration</span>
Because they can comfortably stay out and about
mid-oceanic ranges I believe.
