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Law Incorporation [45]
2 years ago
12

A toy rocket is a composite of a cylindrical body with a cone for a nose. The base of the cylinder and cone are the same size. C

alculate the entire volume of the rocket if the radius of the base is 2 inches, the height of the cone tip is 4 inches, and the height of the entire rocket is 12 inches.
Mathematics
1 answer:
inysia [295]2 years ago
6 0

The volume of the entire rocket given the volumes of the cylindrical body and the cone nose is 117.23 in³.

<h3>What is the volume of the entire rocket?</h3>

The volume of the entire rocket is the sum of the volume of the cylinder and the volume of the cone.

Volume of the cylinder = πr²h

Where:

  • π = 3.14
  • r = radius 2
  • h= height = 12 - 4 = 8 inches

3.14 x 2² x 8 = 100.48 in³

Volume of the cone = 1/3 πr²h

1/3 x 2² x 3.14 x 4 = 16.75 in³

Volume of the rocket = 100.48 + 16.75 = 117.23 in³

To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

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\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

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\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

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