Answer:
6 3/4 (six and three fourths)
Step-by-step explanation:
First, we must turn 4 6/7 into an improper fraction, AKA 28/7. Now, you can't subtract 1/4 from 28/7, can you? So what you need to do is find the greatest common factor of 4 and 7. The GCF would be 28 (7 x 4 = 28, 4 x 7 = 28).
Now we know that the GCF is 28, we can turn the numbers into 28/28 and 1/28. But wait! We aren't done yet. Now we have to change the numerators. Since you multiplied the denominator (7) by 4 to get 28, you must now multiply 28 by 4 as well. (If you do something to the bottom, you have to do it to the top!) Because of this, we are now at 196/28.
Next, we must do the numerator of 1/28. Since we multiplied the denominator (4) by 7 to get 28, we must now multiply 1 by 7. This gets you to 7/28.
It's finally time to subtract. 196 - 7 is 184, so we are at 184/28. But hey, that's an improper fraction! You have to simplify. 184 divided by 28 is 6.75. 0.75 is 3/4 when turned into a fraction.
Mash 6 and 3/4 together, and you've got your answer! 6 3/4.
Answer:
b
Step-by-step explanation:
Answer:
C . 2,550 bolts. lol
Step-by-step explanation:
A simple technique to answer a question like this is to
Step 1: multiply 30 by 17000 = 510000
Step 2: divide 510000 by 200 = 2550
Answer:
From our calculations the large jar is the best value for money because a penny buys more honey
Step-by-step explanation:
<h2>In this problem we are expected to determine which purchase of honey is the cheapest ? large jar or small jar ?.</h2><h2 />
We will determine which has the best value for money using the quantity a pound can purchase.
firstly for the large jar.
if £4.10 will purchase 540g of honey then,
£1.00 will purchase xg
cross multiplying to find x will have
Hence for the large jar a penny would buy 131.7g of honey
secondly for the small jar
if £2.81 will purchase 360g of honey then,
£1.00 will purchase xg
cross multiplying to find x will have
Hence for the small jar a penny would buy 128.1g of honey
Answer:
3
Step-by-step explanation:
3 pounds were picked per hour
