22000=15000(1+.089/4)^4t
22/15=(1.02225)^4t
log(22/15)=4tlog1.02225
(log(22/15)/4log1.02225)=t
(.16633/.038228)=t
t=4.35 years or 4 years and approximately 4 months
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
</span>
Um.. listen to the teacher more
Consecutive numbers would be like 2 and 3, or 7 and 8.
All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.
1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>
</em>
