According to the information given in the exercise, the following expression represents the area of the rectangular garden:
And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:
You can identify that the word "combined" indicates that that expression was obtained by adding both areas.
Knowing the above, you can set up the following equation:
Where "A" is the area of the walkway around the rectangular garden.
Solving for "A", you get the following expression:
The answer is:
540 degrees is equivalent to 180 degrees. Cotangent and cosecant are invalid, sine, secant, tangent are all 0 and cosine is -1.
-20+14m=10m+16
-10m. -10m
-20+4m=16
+20. +20
4m=36
/4. /4
m=9
is proved
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Solution:</u></h3>
Given that,
------- (1)
First we will simplify the LHS and then compare it with RHS
------ (2)
Substitute this in eqn (2)
On simplification we get,
Cancelling the common terms (sinx + cosx)
We know secant is inverse of cosine
Thus L.H.S = R.H.S
Hence proved
Answer:
y-6 = -2(x+1)
Step-by-step explanation:
First we need to find the slope
m = (y2-y1)/(x2-x1)
= (-2-6)/(3--1)
= (-2-6)/(3+1)
= -8/4
= -2
Then we can point slope form where
y -y1 = m(x-x1)
where m is the slope and x1,y1 is a point
y-6 = -2(x--1)
y-6 = -2(x+1)
