5/8 . 3/2 is 15/16
So the answer is D
Answer:
Step-by-step explanation:
r
sin
θ
=
−
3
Explanation:
Imagine we have a point
P
with Rectangular (also called Cartesian) coordinates
(
x
,
y
)
and Polar coordinates
(
r
,
θ
)
.
The following diagram will help us visualise the situation better:
https://keisan.casio.com/exec/system/1223526375
https://keisan.casio.com/exec/system/1223526375
We can see that a right triangle is formed with sides
x
,
y
and
r
, as well as an angle
θ
.
We have to find the relation between the Cartesian and Polar coordinates, respectively.
By Pythagora's theorem, we get the result
r
2
=
x
2
+
y
2
The only properties we can say about
θ
are its trigonometric functions:
sin
θ
=
y
/
r
⇒
y
=
r
sin
θ
cos
θ
=
x
/
r
⇒
x
=
r
cos
θ
So we have the following relations:
⎧
⎪
⎨
⎪
⎩
r
2
=
x
2
+
y
2
y
=
r
sin
θ
x
=
r
cos
θ
Now, we can see that saying
y
=
−
3
in the Rectangular system is equivalent to say
r
sin
θ
=
−
3
Answer link
Jim G.
May 19, 2018
r
=
−
3
sin
θ
Explanation:
to convert from
cartesian to polar
∙
x
x
=
r
cos
θ
and
y
=
r
sin
θ
⇒
r
sin
θ
=
−
3
⇒
r
=
−
3
sin
θ
<h3>
Answer: Third choice. 
</h3>
==================================================
Explanation:
SAS stands for Side Angle Side. Note how the angle is between the two sides. To prove the triangles congruent with SAS, we need to know two sides and an angle between them.
We already see that BC = CD as shown by the tickmarks. Another pair of sides is AC = AC through the reflexive theorem.
The missing info is the angle measures of ACB and ACD. If we knew those angles were the same, then we could use SAS to prove triangle ACB is congruent to triangle ACD.
It turns out that the angles are congruent only when they are 90 degrees each, leading to AC being perpendicular to BD. We write this as 
. The upside down T symbol meaning "perpendicular" or "the two segments form a right angle".
Answer:
a. x > 0.2
Step-by-step explanation:
In either order, subtract the left-side constant and divide by the x-coefficient.
3x +2.4 > 3
3x > 0.6 . . . . . . subtract 2.4
x > 0.2 . . . . . . . divide by 3
__
or
x + 0.8 > 1 . . . . divide by 3
x > 0.2 . . . . . . . subtract 0.8
