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swat32
2 years ago
13

PLEASE HELP NOW DUE TODAY I WILL MARK YOU ALL AS BRAINLIESTS

Mathematics
1 answer:
yuradex [85]2 years ago
4 0

Answer:

42, 44, 45, 46, 48, 49

Step-by-step explanation:

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Solving the following system using the elimination of substitution method.<br> 5a+3b=11<br> -2a+3=b
PSYCHO15rus [73]

Answer:

a = -2

b = 7

Step-by-step explanation:

5a+3b=11

-2a+3=b

substitute for b:

5a + 3(-2a + 3) = 11

5a -6a + 9 = 11

-a = 2

a = -2

b = 7

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2 years ago
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Inessa [10]

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8 and 6 is the answer.......

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What is the product?
Sphinxa [80]

Answer:

[6 12 2]

[0 0 0]

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Step-by-step explanation:

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1 year ago
Rationalize the denominator of square root of negative 49 over open parentheses 7 minus 2 i close parentheses minus open parenth
navik [9.2K]

The answer is the option d, which is: d) \frac{-77+21i}{130}

The explanation for this problem is shown below:

1. Smplify the denominator and rewrite the numerator in this form:

\frac{7i}{7-2i-4-9i} \\\frac{7i}{3-11i}

2. Multiply the denominator and the numerator by the conjugated (3+11i) and simplify the expression, as following:

\frac{7i(3+11i)}{(3-11i)(3+11i)} \\ \frac{21i+77i^{2}}{121+9}  \\ \frac{-77+21i}{130}

3. As you can see, you obtain the expression shown in the option mentioned above.

3 0
3 years ago
Use the product, quotient, and power rules of logarithms to rewrite the expression as a single logarithm. Assume that all variab
Viefleur [7K]

Answer:

log(x^7·y^2)

Step-by-step explanation:

The applicable rules are ...

... log(a^b) = b·log(a)

... log(ab) = log(a) +log(b)

_____

The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.

The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.

Now, you have the sum ...

... log(x^7) +log(y^2)

The second rule tells you this can be rewritten as ...

... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection

5 0
2 years ago
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