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3 years ago

Can someone please help me answer this question, and please help me how you arrived to your correct answer? thank you!

Mathematics

1 answer:

galben [10]3 years ago

3 0

$\sqrt{ - 180 {x}^{16} } \\ = \sqrt{( - 1) \times \: 2 \times 2 \times 3 \times 3 \times 5 \times {x}^{8} \times {x}^{8} } \\ = (2 \times 3 \times {x}^{8} ) \sqrt{( - 1) \times 5 } \\ = 6 {x}^{8} \times \sqrt{ - 1} \times \sqrt{5} \\ = 6 {x}^{8} i \: \sqrt{5}$

so answer is option 4

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Two rentalCar companies charge different prices when you rent a car. Company a charges $.28 per mile and a $50 fee. Company B ch

NARA [144]

Answer:

100 miles

Step-by-step explanation:

Create equations.

Company A: y = 0.28x + 50

Company B: y = 0.78x

These are equal to each other.

0.78x = 0.28x + 50

0.5x = 50

x = 100

7 0

2 years ago

2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?

NNADVOKAT [17]

Standard form: ax^2 + bx + c = y

Steps to simplify:

2x^2 - 1 = 3x + 4

~Subtract (3x + 4) to both sides

2x^2 - 1 - 3x + 4 = 3x + 4 - 3x + 4

~Simplify

2x^2 - 3x - 5 = 0

(a = 2, b = -3, c = -5)

Now that we know what these values are, we can use the quadratic formula to solve.

$x=\frac{-b-+\sqrt{b^2-4ac} }{2a} \\x = \frac{-(-3)-+\sqrt{-3^2-4(2)(-5)} }{2(2)}\\x= \frac{-3-+\sqrt{49} }{4} \\x=\frac{3-+7}{4} \\x = \frac{10}{4}~or~\frac{-4}{4} \\x=\frac{5}{2}~or~-1$

Answer: x = 5/2 or x = -1

Best of Luck!

5 0

3 years ago

Grumpy Corp drug tests all of the recent college graduates it hires each year. The drug test currently used correctly determines

Vedmedyk [2.9K]

Answer:

Hence, the probability of a Negative test is $P(T^C)=0.5904$ .

Step-by-step explanation:

(a)

Let $D=$ Drug user and $T=$ Test positive

Probability of drug users $P(D)=36\%=0.36$

$P(\frac{T}{D})=96\%=0.96$

$P(\frac{T^c}{D^c})=90\%=0.90$

(b)

Find the Probability of a Negative test,

$P(T^C)=P(\frac{T^C}{D^C})\cdot P(D^C)+P(\frac{T^C}{D})\cdot P(D)$

$\Rightarrow P(T^C)=0.9\cdot(1-0.36)+(1-0.96)\cdot 0.36$

$\Rightarrow P(T^C)=0.9\cdot 0.64+0.04\cdot 0.36$

$\Rightarrow P(T^C)=0.576+0.0144$

$\Rightarrow P(T^C)=0.5904$

4 0

2 years ago

Given: △FKL, FK=a, m∠F=45°, m∠L=30° Find: FL

drek231 [11]

The best way to do this is to draw a picture of ΔFKL and include line segment KM that is perpendicular to FL. This creates ΔFKM which is a 45°-45°-90° triangle and ΔLKM which is a 30°-60°-90° triangle.

Find the lengths of FM and ML. Then, FM + ML = FL

FM

ΔFKM (45°-45°-90°): FK is the hypotenuse so FM = $\frac{a}{\sqrt{2}} = \frac{a\sqrt{2} }{2}$