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3 years ago

Can someone please help me answer this question, and please help me how you arrived to your correct answer? thank you!

Mathematics

1 answer:

galben [10]3 years ago

3 0

$\sqrt{ - 180 {x}^{16} } \\ = \sqrt{( - 1) \times \: 2 \times 2 \times 3 \times 3 \times 5 \times {x}^{8} \times {x}^{8} } \\ = (2 \times 3 \times {x}^{8} ) \sqrt{( - 1) \times 5 } \\ = 6 {x}^{8} \times \sqrt{ - 1} \times \sqrt{5} \\ = 6 {x}^{8} i \: \sqrt{5}$

so answer is option 4

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Find the distance between A and B.

Papessa [141]

Answer:

The result is $d = 2\sqrt{5}$ units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2}$ Where the first coordinate is $(x_{1},y_{1})$ and the second coordinate is $(x_{2}, y_{2})$ .

-Use the coordinates A and B for the equation:

$d = \sqrt{(2+2)^2 + (2-0)^2}$

-Then, you solve the equation:

$d = \sqrt{(2+2)^2 + (2-0)^2}$

$d = \sqrt{(4)^2 + (2)^2}$

$d = \sqrt{16 + 4}$

$d = \sqrt{20}$

$d = 2\sqrt{5}$

So, therefore the distance is $2\sqrt{5}$ units.

7 0

3 years ago

How do i solve this?

shusha [124]

Answer:

Step-by-step explanation:

You can use Pythagoras Theorem,

$8^{2} + y^{2} = (8\sqrt{6} )^{2} \\ y^{2} = (8\sqrt{6} )^{2} - 8^{2} \\y^{2} = 384 - 64\\y^{2} = 320\\y = \sqrt{320}$

∴ $y = 8\sqrt{5}$

Hope that helps!!

Please mark as Brainliest!!

7 0

2 years ago

Please help me idk this

Pachacha [2.7K]

Answer:

x = 35 degrees

Step-by-step explanation:

the little box on the left side of the ttriangle means that is a 90 degrees angle.

So you add 55 + 90 = 145

Then subtract 180 - 145

which gives you 35

4 0

2 years ago

Read 2 more answers

Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (

MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em> If $\large \bar x$ is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

$\large [\bar x - s, \bar x +s]$

around 95% of the data must fall in the interval

$\large [\bar x -2s, \bar x +2s]$

around 99.7% of the data must fall in the interval

$\large [\bar x -3s, \bar x +3s]$

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0

2 years ago

I need to know 6 50/6 converted to fraction and simpilied

FromTheMoon [43]

$6\frac{50}{6} =6\frac{25}{3}=14\frac{1}{3} =\frac{43}{3}$

Hope this helped

7 0

2 years ago