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zheka24 [161]
3 years ago
12

I need help with this question. I would like a detailed explanation please!(what are the measurements)​

Mathematics
2 answers:
koban [17]3 years ago
8 0
C = 180 - 104
= 76 degrees
since a straight line is 180 degrees. We minus 104 to 180 to get the other side.

A + B + C = 180
38 + B + 76 = 180
B = 180 - 76 - 38
B = 180 - 114
B = 66 degrees
garri49 [273]3 years ago
7 0

Answer:

X = 66

Step-by-step explanation:

A straight line is equal to 180 degrees so if you have one side of that line you can figure out the inside angle.

Now that you have two of the angles inside the triangle add them up. All the interior angles of a triangle will add to 180. So add up 38 and 76 to get 114. Now do 180 - 114, you should get 66

so x = 66

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Which statements are true for the given quadrilaterals? Choose all answers that are correct. A. All trapezoids are quadrilateral
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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
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Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





4 0
2 years ago
Is this table linear or not?
murzikaleks [220]
Yes it’s a straight line wh no curves
7 0
2 years ago
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