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3 years ago

A height is labeled on the triangle below.

Mathematics

2 answers:

12345 [234]3 years ago

4 0

Answer:

Step-by-step explanation:

The height is always perpinducular to the base. The height here is perpendicular to line segment A.

inessss [21]3 years ago

3 0

Answer:

Step-by-step explanation:

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ASAP!!! WILL GIVE BRAINLIEST!!

Ivan

Answer:

Combination without repetition

Step-by-step explanation:

The fruit he chooses doesn’t matter because he’s simply throwing them in his lunch box (so it’s a combination). And because there is a limited amount of fruit it is without repetition.

5 0

3 years ago

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Use an addition property to solve for B

stich3 [128]

Answer:

Step-by-step explanation:

5 0

3 years ago

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Evaluate the determination for the following matrix [144] [522] [155]

Anettt [7]

Matrix :

1    4    4

5 2    2

1    5    5

=> Determinant =

1 * (2*5 - 2*5) - 4 * (5*5 - 1*2) + 4 * ( 5*5 - 2*1)

= 1*(10 - 10) - 4*(25 - 2) + 4*(25 -2) = 1*0 + 4* 23 + 4*(25 - 2) = 0 - 4*23 + 4*23 = 0

Answer: 0

8 0

3 years ago

The scores on a standardized test are normally distributed with the mean of 750 and standard deviation 70. Find the probability

mafiozo [28]

Hey the answer is C.47.7
goodluck!

3 0

3 years ago

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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago