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Stels [109]
3 years ago
14

What are the removable discontinuities of the following function? f (x) = StartFraction x squared minus 36 Over x cubed minus 36

x EndFraction
Mathematics
2 answers:
aivan3 [116]3 years ago
7 0

Answer:

the removable discontinuities are at x = 6 and at x = -6

Step-by-step explanation:

Notice that the function has common binomial factor in numerator and denominator:

f(x)=\frac{x^2-36}{x^3-36x} =\frac{(x-6)\.(x+6)}{x\,(x-6)\.(x+6)}

therefore, the removable discontinuities are those at x= 6 and x = -6 that correspond to zeros common in numerator and denominator, and therefore those associated with the (x + 6) factor, with the (x - 6) factor.

There is a non-removable discontinuity at x = 0.

The discontinuities can be removed by re-assigning the value of f(x) at x=6 (as 1/6), and at x = -6 (as -1/6)

jeyben [28]3 years ago
3 0

Answer:

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

factoring  f(x)  = (x - 6)(x + 6)

                         ----------------

                          x(x - 6)^x + 6)

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Y_Kistochka [10]

Answer: 201.06

Step-by-step explanation:

To find the area of a circle with the radius, square the radius, or multiply it by itself. Then, multiply the squared radius by pi, or 3.14, to get the area. To find the area with the diameter, simply divide the diameter by 2, plug it into the radius formula, and solve as before.

Hope this helps!

6 0
3 years ago
Identify one way to rewrite the expression using the Distributive Property. 2(9 + 3) A. (2 × 9) − (2 × 3) B. (2 × 9) + (9 × 3) C
Dmitry_Shevchenko [17]
The answer is D.

Because you want to find the rewrite way of distributive right? 2(9+3)

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3 0
3 years ago
Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d
mylen [45]

Question not well presented

Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

Answer:

The numerical length of RS is 22

Step-by-step explanation:

Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

4x - 4 = 4x - 10 + 2x - 10 --- collect like terms

4x - 4 = 4x + 2x - 10 - 10

4x - 4 = 6x - 20--- collect like terms

6x - 4x = 20 - 4

2x = 16 --- divide through by 2

2x/2 = 16/2

x = 8

Since, RS = 4x − 10

RS = 4*8 - 10

RS = 32 - 10

RS = 22

Hence, the numerical length of RS is calculated as 22

8 0
3 years ago
If m is positive and k is negative what is m-k
Andrew [12]
M+k because the subtraction sign and negative cancel out to become positive
8 0
4 years ago
Read 2 more answers
H=10 cm <br>r= 7cm <br>calculate the volume of the cylinder ​
Stels [109]

Answer:

V = 1538.6 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2h  where r is the radius and h is the height

V = pi (7)^2 10

V = 3.14 (49)10

V = 1538.6 cm^3

7 0
3 years ago
Read 2 more answers
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