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3 years ago

If you know the LCM of 4 and 5, how could you find the LCM of 40 and 50?

Mathematics

1 answer:

Archy [21]3 years ago

5 0

Answer:

200

Step-by-step explanation:

The LCM of 4 and 5 is 20. Since you know this, you would multiply this LCM by how much you would multiply to get 40 from 4 or 50 from 5.

4 * 10 = 40

5 * 10 = 50

Since you multiply these factors by 10, you would also multiply the LCM by 10.

20 (LCM of 4 and 5) * 10 = 200

The LCM of 40 and 50 is 200.

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A programmer wants to display how the shape of a rectangle with a fixed perimeter of 300 inches can be changed by varying the re

stiv31 [10]

If the rectangle has a fixed width of 300, it means that

$2(l+w)=300 \iff l+w=150 \iff w=150-l$

where $w$ and $l$ are width and length, respetively.

So given the length $l$ , the are would be

$l\times w = l\times (150-l)=-l^2+150l$

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4 years ago

What are the solutions to the following system of equations? Select the correct answer below.

Fed [463]

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3 years ago

Point B is in between A and C in a segment. AB= 22 and BC=30 Find AC

dolphi86 [110]

Answer:

AC = 52

Step-by-step explanation:

Add the segment lengths together.

AB + BC = AC

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3 years ago

Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

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DedPeter [7]

x=−2 and y=−2
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3 years ago

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