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fgiga [73]
3 years ago
7

If you know the LCM of 4 and 5, how could you find the LCM of 40 and 50?

Mathematics
1 answer:
Archy [21]3 years ago
5 0

Answer:

200

Step-by-step explanation:

The LCM of 4 and 5 is 20. Since you know this, you would multiply this LCM by how much you would multiply to get 40 from 4 or 50 from 5.

4 * 10 = 40

5 * 10 = 50

Since you multiply these factors by 10, you would also multiply the LCM by 10.

20 (LCM of 4 and 5) * 10 = 200

The LCM of 40 and 50 is 200.

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Which term describes a system with exactly one solution
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What is the direct variation of y=8x
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8 0
3 years ago
Evaluate (6 + 2i) / (3 –i ).<br> 5/4 + 6/4i<br> 8/5 + 6/5i<br> 20/8 + 12/8i<br> 16/9 + 12/9i
Yuki888 [10]

We are given with a complex no. and need to simplify it , so let's start !!!

Let's assume that :

{:\implies \quad z=\sf \dfrac{6+2\iota}{3-\iota}}

Now , Rationalizing the denominator or in other words multiplying and dividing {z} by the <em>conjugate</em> of the denominator

{:\implies \quad z=\sf \dfrac{6+2\iota}{3-\iota}\times \dfrac{3+\iota}{3+\iota}}

{:\implies \quad z=\sf \dfrac{(6+2\iota)(3+\iota)}{(3-\iota)(3+\iota)}}

{:\implies \quad z=\sf \dfrac{6(3+\iota)+2\iota (3+\iota)}{(3)^{2}-(\iota)^{2}}\quad \qquad \{\because (a-b)(a+b)=a^{2}-b^{2}\}}

{:\implies \quad z=\sf \dfrac{18+6\iota +6\iota +2(\iota)^{2}}{9-(-1)}\quad \qquad \{\because (\iota)^{2}=-1\}}

{:\implies \quad z=\sf \dfrac{18+12\iota -2}{10}}

{:\implies \quad z=\sf \dfrac{16+12\iota}{10}}

{:\implies \quad z=\sf \dfrac{16}{10}+\dfrac{12\iota}{10}}

{:\implies \quad {\bf \therefore}\quad \underline{\underline{z=\bf \dfrac{8}{5}+\dfrac{6}{5}\iota}}}

Hence , Option B) <em>(8/5) + (6/5)i</em> is correct :D

7 0
2 years ago
PLEASE HELP ASAP! THIS IS TIMED! WILL MARK BRAINLIEST IF ANSWER IS CORRECT!
IgorC [24]

Answer:

C

Step-by-step explanation:

A compound interest will make much more money in the long term than simple interest. Moreover the name compound gives you the answer already.

Have a great day <3

8 0
2 years ago
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