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3 years ago

If you know the LCM of 4 and 5, how could you find the LCM of 40 and 50?

Mathematics

1 answer:

Archy [21]3 years ago

5 0

Answer:

200

Step-by-step explanation:

The LCM of 4 and 5 is 20. Since you know this, you would multiply this LCM by how much you would multiply to get 40 from 4 or 50 from 5.

4 * 10 = 40

5 * 10 = 50

Since you multiply these factors by 10, you would also multiply the LCM by 10.

20 (LCM of 4 and 5) * 10 = 200

The LCM of 40 and 50 is 200.

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Alinara [238K]

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3 years ago

What is 0.5, 3/16, 0.75, 5/48 to Least to greatest?

Natali [406]

Answer

5/48, 3/16, 0.5, 0.75

Step-by-step explanation:

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3 years ago

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iVinArrow [24]

Answer:

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2 years ago

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VikaD [51]

Answer:

4)x=2

5) (-3,4)

Step-by-step explanation:

4) f(x)=x^2-4x+4-4+5

f(x)=(x-2)^2+1

f(x)=a(x-h)^2+k

Axis of symmetry is x=h

h is 2, so axis of symmetry is x=2

5) f(x)=x^2+6x+9-9+13

f(x)=(x+3)^2+4

f(x)=a(x-h)^2+k

Vertex is (h,k)

So, vertex is (-3,4)

Sorry, I can't answer the first 3, cause I don't understand what a-value, b-value and c-value mean.

And also is this college math, cause I'm in middle-school, and I know how to do it.

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3 years ago

Write an equation of the line containing the point (6,-4) and perpendicular to.the line y=-2x-3

igor_vitrenko [27]

Answer:

$y=\frac{1}{2}x-7$

Step-by-step explanation:

So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.

First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

$m_1\cdot m_2=-1$

Plug -2 for one of the slopes.

$-2\cdot m_2=-1$

Divide by -2 to find the slope of our line.

$m_2=1/2$

Thus, our line needs to have a slope of 1/2.

Now, let's use the point-slope form. The point-slope form is given by:

$y-y_1=m(x-x_1)\\$

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

$y-(-4)=\frac{1}{2}(x-6)\\$

Simplify and distribute:

$y+4=\frac{1}{2} x-3$

Subtract 4 from both sides:

$y=\frac{1}{2}x-7$

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.

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3 years ago