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Vilka [71]
3 years ago
9

A cab charges $1.75 for the flat fee and $0.25 for each mile. Write and solve an inequality to determine how many miles Eddie ca

n travel if he has $15 to spend
Mathematics
2 answers:
Bingel [31]3 years ago
6 0
.25x + 1.75= $15
× is each mile
Anuta_ua [19.1K]3 years ago
4 0
Equation-
1.75 +0.25m = x

Solution
1.Subtract the Flat Fee First:
15-1.75 = 13.25

2.Divide by how much a mile cost:
13.25/0.25 = 53miles

3.Solution:
53miles 
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HHHHHHHHHHHHEEEEEEELLLLLLLPPPPPPPPPPPP
Luden [163]

Answer:

A) 20

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
David and Ashley want to calculate $8.27 – $2.98 by first calculating $8.27 – $3 = $5.27. David says that they must subtract $0.
Ierofanga [76]

Number lines are used to represent numbers on a line at a regular interval.

<em>David's statement is correct, while Ashley is incorrect</em>

The expression is given as:

\mathbf{8.27 - 2.98}

<u>Using number lines</u>

The end result on David's number line is 5.29, while the end result on Ashley's number line is 5.25

The correct result of the expression \mathbf{8.27 - 2.98} is 5.29 shows that David is correct

See attachment for the number lines that illustrate <em>David and Ashley's statements</em>

<u>Another way</u>

David's statement can be expressed as:

\$8.27 - \$3 - \$0.02 = \$5.29

While, the expression for Ashley's expression is:

\$8.27 - \$3 + \$0.02 = \$5.25

The original expression is:

\$8.27 - \$2.98 = \$5.29

By comparing the above expressions, we can conclude that <em>David is correct</em>

Read more about number lines at:

brainly.com/question/18611090

4 0
3 years ago
An operation manager at an electronics company wants to test their amplifiers. The design engineer claims they have a mean outpu
andreyandreev [35.5K]

Answer:

The probability that the mean amplifier output would be greater than 364.8 watts in a sample of 52 amplifiers is 0.3156

Step-by-step explanation:

Mean output of amplifiers = 364

Standard deviation = \sigma = 12

We have to find the probability that the mean output for 52 randomly selected amplifiers will be greater than 364.8. Since the population is Normally Distributed and we know the value of population standard deviation, we will use the z-distribution to solve this problem.

We will convert 364.8 to its equivalent z-score and then finding the desired probability from the z-table. The formula to calculate the z-score is:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }

x=364.8 converted to z score for a sample size of n= 52 will be:

z=\frac{364.8-364}{\frac{12}{\sqrt{52} } }=0.48

This means, the probability that the output is greater than 364.8 is equivalent to probability of z score being greater than 0.48.

i.e.

P( X > 364.8 ) = P( z > 0.48 )

From the z-table:

P( z > 0.48) = 1 - P(z < 0.48)

= 1 - 0.6844

= 0.3156

Since, P( X > 364.8 ) = P( z > 0.48 ), we can conclude that:

The probability that the mean amplifier output would be greater than 364.8 watts in a sample of 52 amplifiers is 0.3156

8 0
4 years ago
3 sailboats to 6 fan boats
kolbaska11 [484]
If you are looking for the ratio it would be 1:2
3 0
4 years ago
Show that (4p^2-3q)^2+48p^2q =(4p^2+3q^2)​
Brut [27]

Given:

The statement is

(4p^2-3q)^2+48p^2q=(4p^2+3q^2)

To prove:

The given statement.

Solution:

We have,

(4p^2-3q)^2+48p^2q=(4p^2+3q^2)

Now,

LHS=(4p^2-3q)^2+48p^2q

Using (a-b)^2=a^2+b^2-2ab, we get

LHS=(4p^2)^2+(3q)^2-2(4p^2)(3q)+48p^2q

LHS=(4p^2)^2+(3q)^2-24p^2q+48p^2q

LHS=(4p^2)^2+(3q)^2+24p^2q

It can be rewritten as

LHS=(4p^2)^2+(3q)^2+2(4p^2)(3q)

Using (a+b)^2=a^2+b^2+2ab, we get

LHS=(4p^2+3q^2)

LHS=RHS

Hence proved.

5 0
3 years ago
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