So to find the discriminant of a quadratic equation, the formula is b² - 4ac with a = x² coefficient, b = x coefficient, and c = constant. In this case, our equation is 
Firstly, solve the multiplications and the exponents: 
Next, subtract and we find that our discriminant is 0.
*Additional Info: Since the discriminant is zero, this means that this quadratic equation has 1 real solution.
Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
158, 164, 170, 176, 182, 188