Answer: 3/5
Step-by-step explanation: Using the place value chart, we can see that the decimal 0.6 is 6 tenths. So we can write 0.6 as the fraction 6/10.
Notice however that 6/10 is not in lowest terms.
So we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.
So if we divide the numerator and denominator by 2, we get 3/5.
So 0.6 can be written as the fraction 3/5 which is in lowest terms.
Image provided showing the place value chart.
1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3
Hello,
Answer B.
Using Thales, 6/9=B/8==>B=48/9=5+1/3.
If it is the question I just completed it should be A. 76.4
No she will have more than enough paint have a wonderful evening
