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Answer:
Step-by-step explanation:
Given that in a certain store, there is a .03 probability that the scanned price in the bar code scanner will not match the advertised price.
Here X the number of items that will not match in the sample of 780 items is binomial because
i) there are two outcomes only
ii) Also each trial is independent of the other.
a) the expected number of mismatches
b) Var(x) =
Std dev (X) = 4.7642