Answer:
Hope this helps :)
Step-by-step explanation:
8(x - 2) = 2x + 8
y+9 = -2(y + 1)
value of x in 8(x - 2) = 2x + 8
x=4
substitue
y+9=−2(y+1)
value of y y+9=−2(y+1)
y= - 11/3 or 3.66...
x=4
y=4 (I rounded 3.66)
D,A,B,C i think this is correct !
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Therefore
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
( using the property
)
( using the property 
( combining the like powers )
( using the property
)

( using the property
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Answer:
-10, -|-8|, -(-2), |-11|, 5²
Step-by-step explanation: