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Liula [17]
2 years ago
9

Which quantity is proportional to 90⁄2? Check all that are true. 45⁄1 15⁄3 180⁄3 180⁄4 270⁄8

Mathematics
1 answer:
Sati [7]2 years ago
6 0

Answer:

45/1 and 180/4

Step-by-step explanation:

1. True

\dfrac{90}{2}=\dfrac{45\cdot 2}{1\cdot 2}=\dfrac{45}{1}

2. False

\dfrac{15}{3}=\dfrac{3\cdot 5}{3\cdot 1}=\dfrac{5}{1}\neq \dfrac{45}{1}

3. False

\dfrac{180}{3}=\dfrac{60\cdot 3}{3\cdot 1}=\dfrac{60}{1}\neq \dfrac{45}{1}

4. True

\dfrac{180}{4}=\dfrac{45\cdot 4}{1\cdot 4}=\dfrac{45}{1}

5. False

\dfrac{270}{8}=\dfrac{135\cdot 2}{4\cdot 2}=\dfrac{135}{4}\neq \dfrac{45}{1}

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PLZ HELP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST What is the slope-intercept form of the equation of the line that passes
grigory [225]

Answer:

A.

Step-by-step explanation:

We are given the two points (2,7) and (4,-1).  In order to determine the linear equation, we need to find the slope and the y-intercept. First, find the slope <em>m.</em> Let (2,7) be x1 and y1, and let (4,-1) be x2 and y2:

m=\frac{y_2-y_1}{x_2-x_1} =\frac{-1-7}{4-2}=-8/2=-4

Thus, the slope is -4.

Now, to find the y-intercept, we can use the point-slope form. Recall that the point slope form is:

y-y_1=m(x-x_1)

Where (x1, y1) is a coordinate pair and m is the slope.

Use either of the two coordinate pair. I'm going to use (2,7). Substitute them for x1 and y1, respectively:

y-(7)=-4(x-(2))\\y-7=-4x+8\\y=-4x+15

This is also slope-intercept form. The answer is A.

7 0
3 years ago
Read 2 more answers
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
Charra [1.4K]

Answer:

the download cost for a song is $1 and $11 for a movie

Step-by-step explanation:

According to the questions, the following equations are as follows:

Let us assume the song be x

And, the movies be y

So,

20x + 13y = $163.........(i)

13x + 13y = $156........(ii)

Now solve substract second equation from the first equation

7x = $7

x = $1

And the y value is

20 + 13y = $163

13y = $163 - $20

13y = $143

y = $11

Hence, the download cost for a song is $1 and $11 for a movie

5 0
2 years ago
The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?
Aleks04 [339]

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

  • The selling price of a box of crackers is $1.75
  • You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = \frac{New-Old}{old} × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = \frac{2.54-1.75}{1.75} × 100%

∴ The markup percentage = \frac{0.79}{1.75} × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

#LearnwithBrainly

8 0
3 years ago
Read 2 more answers
I need help.. i really want to go sleep.. thank you so much...
Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given  \sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}

To verify that the above equality is true or false:

Now find \sum\limits_{k=0}^8\frac{1}{k+3}

Expanding the summation we get

\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3} \sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

Now find \sum\limits_{i=3}^{11}\frac{1}{i}

Expanding the summation we get

\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

 Comparing the two series  we get,

\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i} so the given equality is true.

2) Given \sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}

Verify the above equality is true or false

Now find \sum\limits_{k=0}^4\frac{3k+3}{k+6}

Expanding the summation we get

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}

now find \sum\limits_{i=1}^3\frac{3i}{i+5}

Expanding the summation we get

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}

Comparing the series we get that the given equality is false.

ie, \sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}

6 0
3 years ago
What plus 5/9 equals 1/6
pickupchik [31]
-7/18 is what you need to get 1/6 with 5/9
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3 years ago
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