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eduard
3 years ago
11

For the trinomial x2 + 10x + 21, we want to find two binomial factors

Mathematics
1 answer:
ratelena [41]3 years ago
7 0
X^2 + 10X + 21

(X + 3)(X + 7)
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x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \  0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \  0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \  0

Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}
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3 years ago
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e-lub [12.9K]

Answer:

y=-3

Step-by-step explanation:

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