For the right triangle to be given in name of three letters such as this, the right angle is most likely to be in the center, in this case letter K. To determine the common trigonometric properties of a certain angle we may use of the mnemonics SOH - CAH - TOA.
sin angle = opposite side / hypotenuse
cosine angle = adjacent side / hypotenuse
tangent angle = opposite side / adjacent side
If we let small letter j, k, and l be the sides opposite to angles J, K, and L, respectively. Then, the cos (L) will be,
cos (L) = j/k
Parallel lines have the same slope. for example, the two lines y = 6x + 3 and
y = 6x - 5 are parallel because they have the same slope, 6x.
the slopes of perpendicular lines are opposite reciprocals, which means that you would flip the numbers of the fraction and make it negative. for example, the opposite reciprocal of -3x is 1/3x.
also, parallel lines never intersect, whereas perpendicular lines intersect at a 90 degree angle.
therefore, it isnt possible for two lines to be both parallel and perpendicular.
<span>The check is written and signed by the drawer. A drawer is the maker or the writer of a bill of exchange (such as a cheque) who directs the drawee (such as a bank) to pay the stated amount to a third party (the payee). If the bank charged another company's check against Shoe Depots account, this would be included on the bank reconciliation as an addition to the balance per bank.</span>
First, note that
is always positive (except for x=0), so
must be always negative.
Thus, the only plausible graphs are 1 and 3 since they are below the x-axis.
Now,
and
are only defined for x≥0, because only for these x'es we can take the square root.
Note that the third graph has domain (-infinity, 0], so it is not the right one, while 1 is ok.
Answer: first graph
Initial Conditions:
length=L= 10 cm = (10*10⁻²)m
Diameter=D= 2 cm= (2*10⁻²)m
Radius= r= 0.01m
Area=A= π*r²/2 =1.57*10⁻⁴ m²
Resistance=R= 600 ohm
So, from initial conditions we find resistivity(р)
R=рL/A
R*A /L=р
(600)*(1.57*10⁻⁴)/(10*10⁻²)=р
р=0.942 Ω m
<span>As, material remains same so resistivity(p) doesn't change
</span>Lenght= L1= 15 fm= 15*10⁻¹⁵ m
Diameter= D1 = 5 cm= 5*10⁻² m
Radius= r= 0.025 m
Area= A1= π*r²/2 =9.8125*10⁻⁴ m²
R=р*L1/A1
R=(0.942 )*(15*10⁻¹⁵ )/(9.8125*10⁻⁴)
R=1.44*10⁻¹¹ Ω
