3(2x + 6) = 2(4x – 5)

1 answer:

6 0

Answer:

x = 14

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sergij07 [2.7K]

Answer:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

Rewrite as:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}$

Apply law of indices

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

8 0

2 years ago

dexar [7]

Answer: true

Step-by-step explanation:

Hope this helps

8 0

2 years ago

german

Using linear function concepts, it is found that:

a) It costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
b) f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.

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A <em>linear function </em>has the format given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change, that is, how much y changes when x changes by 1.
b is the y-intercept, which is the value of y when x = 0.

The equation for the cost of h kilowatt hours (kWh) of electricity used in excess of 250 kWh is of:

$C = f(h) = 37.6 + 0.1h$