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3 years ago

3(2x + 6) = 2(4x – 5)

Mathematics

1 answer:

maxonik [38]3 years ago

6 0

Answer:

x = 14

....................

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Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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7 0

1 year ago

What are the coefficients in this expression? 2x +9y+(-4) Select all that apply.

zalisa [80]

A) 2 and B) 9
Coefficients are the numbers in front of a variable. The x and y wouldn’t be considered coefficients.

6 0

3 years ago

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Use the foil method to find the product below. (x+3) (x^2-6x)

Scorpion4ik [409]

x^3 - 3x^2 - 18x

Using the FOIL method, I arrived at my solution!

5 0

2 years ago

60 is what percent of 48?

Yakvenalex [24]

Answer:

80%

Inverted = 125%

Step-by-step explanation:

Simplify the fraction to the most simpliest number, which is 4/5. 4/5 = 80%.

If it’s inverted (as in 60/48), the most simpliest number is 5/4. 5/4 = 125%.

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3 years ago

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Which statement is NOT true about the ratio of the leg lengths of increment ΔLRM and increment ΔJSK?

Alona [7]

Given the similar triangles, it can always be noted that similarity can be derived from the proportionality of the leg lengths, however it is not true the the ratio of the proportion of the leg lengths is equal to the slope of the triangles. Thus the false statement is:
A] <span>The slope of the hypotenuse is represented by the ratio of the leg lengths.</span>

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3 years ago