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Airida [17]
3 years ago
10

Find the vertex of the graph of the function. f(x) = 3x^2 - 18x + 24

Mathematics
2 answers:
harkovskaia [24]3 years ago
4 0

Answer:

(3, - 3 )

Step-by-step explanation:

Given a quadratic in standard form

f(x) = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = 3x² - 18x + 24 ← is in standard form

with a = 3, b = - 18

x_{vertex} = - \frac{-18}{6} = 3

Substitute x = 3 into the equation for corresponding value of y

f(3) = 3(3)² - 18(3) + 24 = 27 - 54 + 24 = - 3

vertex = (3, - 3 )

vovangra [49]3 years ago
3 0

Answer:

Step-by-step explanation:

f(x) = 3x² - 18x + 24

f(x) = 3(x²-6x +8)

f(x) = 3 ((x² -6x+9) - 9) +8)

f(x) = 3 ( (x-3)²- 1 )

f(x) = 3(x-3)² - 3

note : the vertex of the graph of the function. f(x) = a(x-h)² + k is the point : (h;k)

in this exercice the vertex is : (3; -3 )

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