Since the area of the circle is only 3.14. that means 3.14 out of one hundred units can be hit. so you have a 3.14% chance of hitting the circle in the middle. SO the probability is very close to 0.
100 - 3.14 = 96.86, so we have a 97 percent chance (approximately) of landing in the white space, This is very close to one.
Answer:
3 twelths is your answer :)
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is

Answer:
C
Step-by-step explanation:
The area of that figure is 2453.25 square feet
First, you would need to find the area of the rectangle
(L)(W)
(70)(30)
2100
Then since it is only a semi circle, the formula is pi*r^2/2
You find the area of a full circle first
(3.14)(15^2)
(3.14)(225)
706.5
Then you divide that by 2 since it’s only half a circle
706.5/2 = 353.25
Finally you add that by the area of the rectangle
2100 + 353.25 = 2453.25 square feet