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Sergio039 [100]
3 years ago
6

• A neighborhood threw a fireworks celebration for the 4th of July. A bottle rocket was launched upward from the ground with an

initial velocity of 160 feet per second. The formula for vertical motion of an object is h(t) = 0.5at2 + vt +s, where the gravitational constant, a, is -32 feet per square second, v is the initial velocity, s is the initial height, and h(t) is the height in feet modeled as a function of time, t.
Part A: What function describes the height, h, of the bottle rocket after t seconds have elapsed?


Part B: What was the maximum height of the bottle rocket?​
Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

poopy

Step-by-step explanation:

Marina CMI [18]3 years ago
5 0

Answer:

h(t)=0.5at^2+v+5

Step-by-step explanation:

If you know how to do math you should know

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Find the equation of the plane through the point p=(5,5,4)p=(5,5,4) and parallel to the plane 5x+2y−z=−6.
Anna35 [415]
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31

Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
7 0
3 years ago
Babcock and Marks (2010) reviewed survey data from 2003–2005 and obtained an average of μ = 14 hours per week spent studying by
Dmitry [639]

Answer:

We do not have enough evidence to accept H₀

Step-by-step explanation:

Normal Distribution

size sample  =  n = 64   (very small sample for evaluating population of 5  years

Standard deviation 4,8

1.- Test hypothesis

H₀             null hypothesis        ⇒               μ₀ = 14       and

Hₐ     alternative hypothesis   ⇒                μ₀ ≠ 14

2.- z(c)  we assume α = 0,05  as we are dealing with a two test tail we should  consider   α/2  = 0.025.

From z table we the z(c) value

z(c) = 1.96           and of course by symmetry   z(c) = -1.96

3.- We proceed to compute z(s)

z(s)  = [ (  μ -  μ₀ ) /( σ/√n) ]           ⇒    z(s)  = - (1.5)*√64/4.8

z(s)  = - 2.5

We compare z(s)  and z(c)

z(s) < z(c)     -2.5  < -1.96  meaning  z(s) is in the rejection zone

we reject H₀ .

From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀

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Step-by-step explanation:

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