Answer:
b. 2.333
Step-by-step explanation:
Test if the mean transaction time exceeds 60 seconds.
At the null hypothesis, we test if the mean transaction time is of 60 seconds, that is:
At the alternate hypothesis, we test if it exceeds, that is:
The test statistic is:
In which X is the sample mean, 
is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
60 is tested at the null hypothesis:
This means that 
A sample of 16 ATM transactions shows a mean transaction time of 67 seconds with a standard deviation of 12 seconds.
This means that 
Value of the test statistic:
Thus, the correct answer is given by option b.
Answer: perimeter = 26.5
Area = 106
Step-by-step explanation:
The given polygon is an octagon. The apotherm which is the perpendicular line from the midpoint of the octagon is 8,
The formula for determining the area of a polygon is expressed as
Area = a² × n × tan 180/n
Where n represents the number of sides of the polygon.
n = 8
Therefore,
Area = 8² × 4 × tan(180/8)
Area = 256 × tan 22.5
Area = 106
The formula for determining the perimeter of a regular polygon is
P = 2 × area/apotherm
Perimeter = 2 × 106/8
Perimeter = 26.5
Ok so this is the first page
1.
78 pizzas. 20% of 65 is 13. Add that to 65 and you get 78 pizzas.
It is a 1.08% decrease. When you divide 65/60 you get 1.08. Im not 100% sure about this one
2.
Online store=$208 and the superstore=$224
The difference is $16 so it would be cheaper to get it at the online store
3.
It is $4000. For the first year you would multiply $20,000 by 5% which is 20000*.05=1000. Then multiply 1000 by 4 years to get $4,000
Instead of multiplying the 1000 by 4, multiply by 2 to get 2000. Subtract 4000-2000 to get 2000. You saved $2,000
Answer:
The answer is
Step-by-step explanation:
we know that
In this problem we have
so
The angle 
belong to the third or fourth quadrant
The value of 
is negative
Step 1
Find the value of
Remember
we have
substitute
------> remember that the value is negative
Step 2
Find the value of 
we have
substitute
