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3 years ago

How do I study for a math test when all I have is my student refrence book/SRB

Mathematics

2 answers:

Oksana_A [137]3 years ago

4 0

You can go to an online website that's about your test.

kolezko [41]3 years ago

4 0

Have someone take the book and create "test questions" for you to answer.

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Enter the sum of numbers as a product of their GCF. 45 + 30

nirvana33 [79]

45 + 30 = 15(3 + 2) = 15(5) = 75

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3 years ago

Calculator

hodyreva [135]

Answer:

Step-by-step explanation:

x = 8

y = 40

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3 years ago

On a lunch counter, there are 3 oranges, 5 apples, and 2 bananas. If 3 pieces of fruit are selected, find the probability that 1

muminat

Answer:

$Probability = \frac{1}{24}$

Step-by-step explanation:

Given

$Oranges = 3$

$Apples = 5$

$Banana = 2$

$Total = 10$

Required

Determine the probability of 1 orange, 1 apple and 1 banana

Since, order is not important:

$Probability = P(Orange) * P(Apple) * P(Banana)$

$Probability = \frac{3}{10} * \frac{5}{9} * \frac{2}{8}$

<em>The difference in the numerator is as a result of picking the fruit without replacement</em>

$Probability = \frac{30}{720}$

$Probability = \frac{1}{24}$

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3 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

2 years ago