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2 years ago

10

1. 7+8-2 .

1 answer:

AnnZ [28]2 years ago

8 0

Answer:

1. 13

2. 11

3. 10

4. 9

5. 12

6. 16

7. 14

8. 40

Step-by-step explanation:

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Dennis_Churaev [7]

Answer:

She will have $71.32.

Step-by-step explanation:

135-(44.8+18.88)=71.32

3 0

2 years ago

Read 2 more answers

The man buys flags 4 his store. each flag cost $28. how many flags can he buy for $350? What does the remainder represent? help

kodGreya [7K]

He can buy 12 flags, the remainder represents his left over money

5 0

3 years ago

Read 2 more answers

Find the area of this irregular polygon.

Rainbow [258]

Answer:

970m^{2}

Step-by-step explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:

$At= \frac{b.h}{2}$

Where:

$H= height = 30 m$

$B = 9 m + 9 m + 20 m = 38 m$

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.

$At= \frac{38 m .30 m}{2}$

$At= \frac{1140 m^{2} }{2}$

$At= 570 m^{2}$

Now we are going to calculate the square's area, that is much more simple:

$As= L^{2}$

Where:

$L=20 m$

$As= (20 m)^{2} = 400m^{2}$

To know the whole figure's area, we add up both areas:

$A = At+As = 570m^{2} +400m^{2}=970m^{2}$

3 0

3 years ago

A fair coin is tossed and a die is rolled. what is the probblloy of the coin being tails and the die landing on a 2

ZanzabumX [31]

The probility of getting a tail is 1 (tail) to 2 total possibilities which will be 1/2. The probility for rolling a "2" is 1 to a total possibility of 6 so the probability of 1/6. Since these are independent events and you want both to happen, you need to multiply the two results which will be 1/2 * 1/6 which equals 1/12.

7 0

2 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

2 years ago