1. 7+8-2 .
1 answer:
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Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore,
⇒
⇒
⇒
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer:
I’m not too sure what your question is exactly but if your just trying to graph the two equations I can help u with that (:
Step-by-step explanation:
The first thing you should do is change the second equation to slope intercept form. It is much easier for most people. From there write out your table by choosing a number for x then plugging that number into the equation to find y. For the first equation (y=1/3x+2) it’s always easier to use multiple of three for the number of x. For example, if 3 was my number for x I would multiply 1/3 by 3=1 then simply add 2=3. So the coordinates for one point on that table would be 3,3. You continue to do that for each graph then plot your points. (In my graph, purple is the equation y+9=-9/3x-9 and black equals the equation y=1/3x+2
