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2 years ago

PLEASEE HELP!

Mathematics

1 answer:

melamori03 [73]2 years ago

7 0

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

$\left | b \right |$ = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

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56+3<br><img src="https://tex.z-dn.net/?f=56%20%2B%203%20%3D%20" id="TexFormula1" title="56 + 3 = " alt="56 + 3 = " align="absmi

tangare [24]

sorry if I'm wrong. I got confused because you put 56+3 twice.×= 63
56+3=59=x-4 (this is with subtraction sign)

I didnt know if that a subtracting or negative so here both

56+3=x-4 (this is with the negative sign)
x= -14.75

6 0

3 years ago

Robert says 12 divide by 3//4 = 9. He used the following steps: 12/1 × 3/4 = 36/4 What error did Robert make? A. Robert used sub

wlad13 [49]

Answer:

C and D are the same answers but one of those.

Step-by-step explanation:

Um, I got what Robert got, so by process of elimination, it must be C or D. I used multiplication, so it wasn't subtraction or addition. Meaning whatever a reciprocal is, I didn't do that.

8 0

2 years ago

Pls help

solong [7]

Ok let’s solve it

5(x-2)^2-20=0

first let’s foil (x-2)

5(x^2-4x+4) -20=0

now distribute the 5

5x^2 -20x +20 -20 = 0

combine like terms

5x^2-20x=0

take the gcf

5x(x-4)=0

x=0, 4

solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k

7 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Llana [10]

Define your two QUESTIONS

Write your system of EQUATIONS

SOLVE the system of equations.

Find the SOLUTION to the question being asked.

6 0

3 years ago

Determine to the nearest and tenth the surface area of a tin can with a radius of 8 centimeters and a height of 16 centimeters

trapecia [35]

Answer:

1206 square centimeters

Step-by-step explanation:

Hello, I can help you with that

a tin is a cylinder,a cylinder is formed by 2 circles anda 1 rectangle

let's remember

Area of the circle

$A=\pi *radius^{2}$

Area of the rectangle

$A_{r}=length *wide\\$

the length of the rectangle is the height of the tin (16 cm)

and the wide is equal to the perimeter of the circle

perimeter of the circle(P)

$P=2*\pi *radius$

so, the area of the rectangle is

$A_{r}=length *wide\\\\A_{r}=heigth *2*\pi *radius$

Step one

find the total area:

the total area is equal to 2 circles + 1 rectangle

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)$

Step two

put the values into the equation

height = 16 cm

radius= 8 cm

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)\\A_{total}=(2* \pi )+(16*2*\pi *8)\\A_{total}=(128* \pi )+(256*\pi )\\A_{total}= 378 \pi\\ A_{total}=1206.37$

so, the total area is 1206.37 square centimeters

I hope it helps, have a great day.

6 0

3 years ago

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