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jeyben [28]
3 years ago
10

PLEASEE HELP!

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

\left | b \right | = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

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Lena [83]

Answer:

second one:  -4x +6

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fourth:   245x + 30

fifth: 81x - 21x

(last one) sixth: 1600x + 8x

( if this goes wrong then I did  something else)

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3 years ago
Select all the expressions equvilants to 1.5 x 4 + 3 x 2 - 7
Step2247 [10]
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2 years ago
What is the equation of the line that passes through the point (-2,7) and has a slope of zero​
Lina20 [59]

Answer:

Equation of the line that passes through the point (-2,7) and has a slope of zero​ is given as

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Step-by-step explanation:

Equation of line is given as

y-y_1=m(x-x_1)   -----------(1)

Here

m=0 \ \ \ and \ \ \ (x_1, y_1) = (-2, 7)

Substituting values in equation (1)

y-7=0(x+2)\\y=7

5 0
3 years ago
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Aleks04 [339]
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SVEN [57.7K]

Answer:

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