Solve for b. -3b = 9 - 4b B=

Mathematics

1 answer:

BlackZzzverrR [31]2 years ago

3 0

Answer:

b=9

Step-by-step explanation:

move the 4b over to the other side by adding it to both sides

$-3b(+4b)=9-4b(+4b)$

$1b=9$

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Which of the following equations represents the area of a sector?

Rina8888 [55]

From the given options we can say that the only one that represents the area of the sector is; A = n/360 * πr²

<h3>What is the Area of the Sector?</h3>

In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.

The formula for Area of a sector is given as;

θ/360 * πr²

where;

θ is the central angle of the sector

r is radius

Now, looking at the given options we can say that the only one that represents the area of the sector is;

A = n/360 * πr²

where n is the central angle of the sector

Read more about Area of Sector at; brainly.com/question/16736105

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4 0

1 year ago

PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!

Alex Ar [27]

Start by distributing the exponent to each of the terms in $(2u)^{3}$ . This will become $2^{3} u^{3}$ , and $2^{3} =8$ . Now, the expression is:

$\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }$ .

We can now simplify the bottom to read: $8u^{5}$ because when multiplying variables raised to an exponent, we add the exponents. The expression now looks like:

$\frac{2u^{3} v^{2} }{8u^{5} }$

The 2/8 simplifies to 1/4:

$\frac{u^{3} v^{2} }{4u^{5} }$

Now, we have two u terms on the top and bottom. When dividing variables raised to an exponent, we subtract the exponents. However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent. The final answer is:

$\frac{v^{2} }{4u^{2} }$