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klasskru [66]
3 years ago
9

A leading bank is coming up with an investment that pays 8 percent interest compounded semiannually. What is the investment's ef

fective annual rate (rEAR)?
Mathematics
1 answer:
uranmaximum [27]3 years ago
5 0
The effective rate is calculated in the following way:
r =  {(1 +  \frac{i}{n} )}^{n} - 1
where r is the effective annual rate, i the interest rate, and n the number of compounding periods per year (for example, 12 for monthly compounding).
our compounding period is 2 since the bank pays us semiannually(two times per year) and our interest rate is 8%
so lets plug in numbers:
r = {(1 +  \frac{8\%}{2}) }^{2}  - 1 \\ r =  {(1 +  \frac{1}{25}) }^{2}  - 1 \\ r =  \frac{676}{625}  - 1 \\ r = 0.0816 \: or \: 8.16\%
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The table gives predictions of the average costs of a gasoline car after the year 2030. Which graph best represents the relation
kiruha [24]

Answer:

It's the b graph

Step-by-step explanation:

Khan Academy.

4 0
2 years ago
Read 2 more answers
A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

3 0
3 years ago
Read 2 more answers
A=4ℼR2 solve for R<br> SHOW ALL STEPSSSSSSSSSSSSS
GuDViN [60]

Given problem;

  A  = 4 π R²

  To solve for R, we have to make it the subject of the expression.

Since

      A  = 4 π R² , follow these steps to find R;

    Multiply both sides by \frac{1}{4\pi }  

 A x \frac{1}{4\pi }  =  \frac{1}{4\pi } x 4 π R²

          \frac{A}{4\pi }   = R²

Then find the square root of both sides

        √R²  = \sqrt{\frac{A}{4\pi } }  

            R  = \sqrt{\frac{A}{4\pi } }

The solution is \sqrt{\frac{A}{4\pi } }

3 0
3 years ago
Which lengths could be the sides of a triangle?
galina1969 [7]
345,354,354,341,098cm
5 0
3 years ago
Crystal bowled two games for a total score of 202. Her score for the first game was 30 points less than the score of her first g
vlada-n [284]
X + x -30 = 2022x - 30 = 2022x = 232x =116 first game = 116second game = 116 - 30 = 86116 + 86 = 202 second game = 86
6 0
3 years ago
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