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Sunny_sXe [5.5K]
3 years ago
9

Write the improper fraction as a mixed number 10/7

Mathematics
2 answers:
lubasha [3.4K]3 years ago
7 0

Answer:

10/7 as a mixed number is 1 3/7

Colt1911 [192]3 years ago
5 0

Answer:

1 3/7

Step-by-step explanation:

Step 1:

10/7 = 1 3/7

Answer:

1 3/7

Hope This Helps :)

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A car is said to get 25 miles per gallon on a highway, but this value can fluctuate by 6 miles per gallon, at most. Which of the
Pepsi [2]

Answer:

| x1 -25\ | \leq\ 6 is the correct answer to the given question.

Step-by-step explanation:

Missing information

In this question options are missing.Following are the option

(a) | x1 -25\ | \leq\ 6

(b) | x1 - 6 |\ > 25

(c)| x1 +25 |\ \leq \ 6

(d) | x1 +25 |\ > 6

As mention in the question On the highway, car is said to get 25 miles per gallon

We assume x1= 25

also that the value of x1 is fluctuate by 6 miles per gallon

x1 \leq \ 25\ \pm\ 6

This can be written as

x1\ -25 \leq \  \pm\ 6

Therefore

| x1 -25\ | \leq\ 6 is the answer

8 0
3 years ago
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Sonja [21]

Answer:all

Step-by-step explanation:so because u have done all

3 0
2 years ago
A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let <em>X</em> = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0
3 years ago
What's five names of 64
Tems11 [23]
Multiple factor product divisor and dividend
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3 years ago
THE FLORIDA EVERGLADES WELCOMES ABOUT 2X10^3 VISITORS PER DAY. Basedon this ,about how many visitors come to the everglades per
lesya [120]

Answer:

2·10^3 = 2·1,000 = 2,000

2,000 · 7 = 14,000

6 0
3 years ago
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