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Mekhanik [1.2K]
3 years ago
10

Find the distance between the points given. (-3, -4) and (0, 0)

Mathematics
2 answers:
melomori [17]3 years ago
8 0
The distance between the points is 5
PolarNik [594]3 years ago
3 0

Answer:  The required distance between the given points is 5 units.

Step-by-step explanation:  We are given to find the distance between the points (-3, -4) and (0, 0).

<u><em>Distance formula :</em></u>  The distance between two points (a, b) and (c, d) is given by

D=\sqrt{(c-a)^2+(d-b)^2}.

So, the distance between the given points (-3, -4) and (0, 0) is given by

D=\sqrt{(0-(-3))^2+(0-(-4))^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5.

Thus, the required distance between the given points is 5 units.

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Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

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According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

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Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

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R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

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R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

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