Which numbers are you doing?
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➷ final = original x multiplier^n
n is the number of years
Substitute the values in:
final = 3800 x 1.054^3
final = 4449.440763
The closest answer is A
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Answer:
Step-by-step explanation:
Answer:(A)= (-x^11)/(y^7)
(B)= (1/12xy^5)
Step-by-step explanation:
(A) (3x^3y^-2)(-2x^-3y^2)^-5/(6x^7y^-5)
[(3x^3y^-2)(-2x^15y^-10)]/(6x^7y^-5)
(6x^18y^5)/(-6x^7y^12)
(-6x^11)/(6y^7)
(-x^11)/(y^7)
(B) [(12x^-3y^5)/(x^-4)]^-1
(1/12xy^5)
6 11/96
Sorry i cant explain just know its extremly hard and i recomend the app photo math its the best!
