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liberstina [14]

3 years ago

6

Evaluate the expression for the given value of the variable. 51 + 3/7r. R= - 1/2

1 answer:

mel-nik [20]3 years ago

4 0

The answer is -50.429

You would replace the -1/2 where r is at, divide 7& -1/2, then add it to 51

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Consider the system of equations given below

siniylev [52]

Answer:

its A or C

Step-by-step explanation:

5 0

3 years ago

What is the area of this figure?<br> 6 mi<br> 5 mi<br> 2 mi<br> 2 mi<br> 11 mi<br> 9 mi<br> ורן 7

Alborosie

I can’t see the image maybe if you redo it

5 0

3 years ago

katrin2010 [14]

Answer:

first blank- technological skills

second blank- vision

Step-by-step explanation:

4 0

2 years ago

Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

2 years ago

Please anyone answer me

ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

$A\frac{}{1} = ∫g(x)dx = ∫xdx = \frac{1}{2} {x}^{2} | \frac{2}{0} = 2$

Area 2:

$A\frac{}{2} = ∫(g(x) - f(x))dx$

$= ∫(x - {(x - 2)}^{2} )dx$

$= ∫( - {x}^{2} + 5x - 4)dx$

$= ( - \frac{1}{3}{x}^{3} + \frac{5}{2} {x}^{2} - 4x) | \frac{4}{2}$

$= 2.67 - ( - 0.67) = 3.34$

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0

3 years ago